title: is_contained_in
tags: list,intermediate

Returns True if the elements of the first list are contained in the second one regardless of order, False otherwise.

Use count() to check if any value in a has more occurences than it has in b, returning False if any such value is found, True otherwise.


def is_contained_in(a, b):
  for v in set(a):
    if a.count(v) > b.count(v):
      return False
  return True


is_contained_in([1, 4], [2, 4, 1]) # True