Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters).

Use isalnum() to filter out non-alphanumeric characters, lower() to transform each character to lowercase.
Use collections.Counter to count the resulting characters for each string and compare the results.

代码实现

from collections import Counter

def is_anagram(s1, s2):
  return Counter(
    c.lower() for c in s1 if c.isalnum()
  ) == Counter(
    c.lower() for c in s2 if c.isalnum()
  )

使用样例

is_anagram("#anagram", "Nag a ram!")  # True