Splits values into two groups.
If an element in filter is True, the corresponding element in the collection belongs to the first group; otherwise, it belongs to the second group.

Use list comprehension and enumerate() to add elements to groups, based on filter.

代码实现

def bifurcate(lst, filter):
  return [
    [x for i, x in enumerate(lst) if filter[i] == True],
    [x for i, x in enumerate(lst) if filter[i] == False]
  ]

使用样例

bifurcate(['beep', 'boop', 'foo', 'bar'], [True, True, False, True]) # [ ['beep', 'boop', 'bar'], ['foo'] ]