Returns every nth element in a list.

Use [nth-1::nth] to create a new list that contains every nth element of the given list.

代码实现

def every_nth(lst, nth):
  return lst[nth - 1::nth]

使用样例

every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]